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Ian Crockford
2004-09-20, 01:48
I've a question about how to set up the server to cope with multi-disc
albums.

Currently, the albums in my music collection have been physically stored in
separate directories on my hard disk like:

artist - album name
artist - album name
artist - album name
CD 1
CD 2
artist - album name
artist - album name

etc.

I have set the Album ID3 tags within the double album as "album name (CD 1)"
and "album name (CD 2)".

Can someone please suggest the best way to organise multi-disc albums? I
note the Group Discs option from within the server, and I want to make sure
that each CD gets listed separately (so assume "Treat multi-disc sets as
multiple albums" is the correct setting). However, how should I physically
organise the multiple disks on my hard disk, and how does this function
work? Do I have to make sure that the album ID3 tags are the same for each
disk - and if so, how does the server know which is disc 1 and disc 2, etc?

Many thanks

Ian

Bob Myers
2004-09-20, 08:42
> I've a question about how to set up the server to cope with multi-disc
> albums.

It seems this is one of those topics that comes up over and over.

1. Use iTunes to specify the disc number for each track. I'm sure other
tag editors can do this too.
2. Remove the (n of m) part of the album name tag.
3. Choose the "Treat multi-disc sets as a single album" option.

You may want to then place all the tracks in a single physical
directory, although it doesn't matter.

Personally, I would change the UI to make this more intuitive by
replacing "Treat multi-disc sets as a single album" with "Use the DISC
tag to determine which disc of a multi-disc set the track is on."

An even better solution, in my opinion, would be to change the way this
works. Don't use the DISC tag, which is not standard and many tag
editors cannot set. Instead, do some basic parsing on the album name tag
to find suffixes like (1 of 2) or (Disc 3) and do this automatically.
That's what people want, and how I think the original poster thought it
should work.

--
Bob Myers